SwiftOpenCL
A swift wrapper around OpenCL inspired the C++ object wrapper.
Interfacing with C libraries from Swift is a pain. Alongside this, the OpenCL library is quite verbose to setup a working environment. This is the start of a Swift wrapper around the OpenCL API.
Developers
To generate an Xcode project for development run
swift package generate-xcodeprojUsing Swift Package Manager
Sample Package.swift file
import PackageDescription
let package = Package(
name: "<Project Name>",
dependencies: [
.Package(url: "https://github.com/damienpontifex/SwiftOpenCL.git", majorVersion: 0)
]
)Sample main.swift file
import SwiftOpenCL
#if os(Linux)
//TODO: Add OpenCL module import for Linux
#else
import OpenCL
#endif
let platforms = Platform.all
for platform in platforms {
guard let extensions = platform.getInfo(CL_PLATFORM_EXTENSIONS) else {
continue
}
print(extensions)
}Sample usage
A simple vector addition kernel.
guard let device = Device.default() else {
exit(EXIT_FAILURE)
}
do {
print("Using device \(device)")
let context = try Context(device: device)
let aInput: [cl_float] = [1, 2, 3, 4]
let bInput: [cl_float] = [5, 6, 7, 8]
let a = try Buffer<cl_float>(context: context, readOnlyData: aInput)
let b = try Buffer<cl_float>(context: context, readOnlyData: bInput)
let c = try Buffer<cl_float>(context: context, count: 4)
let source =
"__kernel void add(__global const float *a," +
" __global const float *b," +
" __global float *c)" +
"{" +
" const uint i = get_global_id(0);" +
" c[i] = a[i] + b[i];" +
"}";
let program = try Program(context: context, programSource: source)
try program.build(device)
let kernel = try Kernel(program: program, kernelName: "add")
try kernel.setArgs(a, b, c)
let queue = try CommandQueue(context: context, device: device)
let range = NDRange(size: 4)
try queue.enqueueNDRangeKernel(kernel, offset: NDRange(size: 0), global: range)
let cResult = c.enqueueRead(queue)
print("a: \(aInput)")
print("b: \(bInput)")
print("c: \(cResult)")
} catch let error as ClError {
print("Error \(error.err). \(error.errString)")
}